Failing in test cases

#1

failing in test cases

#2

what is $lt and &lt ??

#3

if(ch[0] >= ‘A’ && ch [0]<=‘Z’){ cout<<‘U’;//updated } not understand this part

#4

after this update
your code will pass all testcases

if(ch[0] >= ‘A’ && ch [0]<=‘Z’)
this condition is true when ch is lie between A and Z that mean
ch is upper case Letter hence print U

#5

hello…

#6

Your Code

#include <iostream>
#include<string>

using namespace std;

void changecase(string name)
{
    

    bool upper;
  
    if (name[0] >= 'A' && name[0] <= 'Z')
    {
       cout<< 'A';
    }
    else if(name[0] >= 'a' && name[0] <= 'z')
    {
        cout<< 'L';
    }
	else{
		 cout<< 'I';
	}
    
}

int main()
{
    // string name = "MaMes";
    // string name = " namES";
    string name;
    getline(cin,name);
    changecase(name);
    return 0;
}

this is completely wrong
read the question carefully
you have to take a character (ch) not a string
and then Write a function that returns ‘U’, if it is uppercase; ‘L’ if it is lowercase and ‘I’ otherwise.

#7

this is still no working

#8

What you have done now
Share the code

#9

#include
#include

using namespace std;

void changecase(string name)
{

if (name[0] >= 'A' && name[0] <= 'Z')
{
   cout<< 'U';
}
else if(name[0] >= 'a' && name[0] <= 'z')
{
    cout<< 'L';
}
else{
	 cout<< 'I';
}

}

int main()
{
string name;
getline(cin,name);
changecase(name);
return 0;
}

#10

hello…

#11

You have not changed anything
Read my previous reply
You didn’t have to use string
Just take a character

Instead of this
Use this
Char ch;
Cin>>ch;
changecase(ch);

#12

Also here instead of string use char
Also replace name[0] with ch

#13

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