Explain the sample test case

#1

Explain the sample test case

#2

hello @t.prateek98
Whenever we input a number, we’ve to output k most frequent numbers in decreasing order, and if frequency of two or more numbers is same print them in increasing order, and if numbers present till now is less than k print all of them following the same criteria for frequency.

Let’s discuss the given example:
1
5 2
5 1 3 5 2
Here t = 1
for the given test case n = 5, k = 2
so let’s see what happend when each number is inputted:-
when the first number 5 is inputted, the numbers present are
5 with frequency 1,
so we only print 5
when 1 is inputted
the numbers present are
5 with frequency 1,
1 with frequency 1,
two numbers with same frequency present, so we output them in increasing order:
We print 1 5
when 3 is inputted,
the numbers present are
5 with frequency 1,
1 with frequency 1,
1 with frequency 1,
three numbers with same frequency present, so we output k of them in increasing order:
We print 1 3
when 5 is inputted
the numbers present are
5 with frequency 2,
1 with frequency 1,
1 with frequency 1,
highest freq is 2, and 2nd highest is 1(for 1, 3 but we can print only 2 numbers, and we’ve to print same frequency numbers In increasing order,
We print 5 1
When 2 is inputted:
the numbers present are
5 with frequency 2,
1 with frequency 1,
1 with frequency 1,
2 with frequency 1
highest freq is 2, and 2nd highest is 1(for 1, 2, 3 but we can print only 2 numbers, and we’ve to print same frequency numbers In increasing order,
We print 5 1
so printed numbers are
5 1 5 1 3 5 1 5 1

#3

give me some another test cases .I dont get my mistake.

#4

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