Doubt

#1

#include
using namespace std;

int keyfound(int a[],int n,int key){
for(int i=0;i<n;i++){
if(a[i]==key){
return i;
break;
}
else{
return-1;
}
}
}

int main() {
int a[100];
int n;
cin>>n;
for(int i=0;i<n;i++){
cin>>a[i];
}
int key;
cin>>key;
cout<<keyfound(a,n,key);
return 0;
}

#2

Hello @discobot,
You are not required to put else condition for if(A[i]==key) , because if you don’t get after checking every element the loop will finish and at the end of the function you will return -1 that is element not found.
correct code will be
int keyfound(int A[],int n,int key){
for(int i=0;i<n;i++){
if(A[i]==key){
return i;//directly it will come out of loop if it returns so no need of break
}
}
return -1; ///if after trversing whole array you don’t get the element
}

#3

Hi! To find out what I can do, say @discobot display help.

#4

i have return the code mentioned by ta bu still my output is not correct here is the code

#5

#include using namespace std; bool linearsearch(int key,int arr[],int n){ for(int i=0;i<n;i++){ if(arr[i]==key){ return i; } } return -1; } int main(){ int arr[100]; int n; cin>>n; for(int i = 0;i<n;i++){ cin>>arr[i]; } int key; cin>>key; cout<<linearsearch(key,arr,n); cout<<endl; return 0; }

#6

Could you pls share the error code you are getting the whole error.

#7

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