int a = 10;
int *ptr = &a;
cout << ptr <<endl;
o/p = 0x7fff15e4efd4
How come an integral pointer ptr store an address containing character ?
Doubt regarding pointer
hi @aggarwal.naman21
Pointer stores the address of the variable… and int *ptr means that ptr is a pointer pointing to an integer variable… int in front of it doesn’t specify that it’s integer variable…
like i thought that if the address is say 0x7fff15e4efd4 , i.e it is a hexadecimal, so we can only see characters from a to f (representing nos form 10 to 15) , so it is an alternate way of representing numbers from 10 to 15 through alphabets .
am I right about it?
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