Doubt regarding conversion from int to array

#1

how should i store a value from int to array

#2

hi @aryaman.harshu I’d suggest you to use a string for this question. Take input for a string, then store the digit to be searched in a character. You can easliy traverse the string after that.

#3
#4

@aryaman.harshu please tell what problem you are facing?

#5

@aryaman.harshu this should be while no != 0 or while no > 0
image

#6

array must be initialized with a brace-enclosed initializer 7 | int a[100] = no;

#7

im getting this error while storing the integer in the array

#8
#9

hi @aryaman.harshu can you tell me what are you trying to do with this line?
image

#10

im trying to store the number in int as well as array so that from in i can find how many digits are there and then use it to read that same number in array so that i can use linear search

#11

@aryaman.harshu yeah you cannot do that.
you will have to manually extract each digit of the number and store it individually in each index if you wish to do that.

#12

so i did extract it in the array altough the number would be reversed but for this question itll work but still im getting 0 as ans

#13

heres the code https://ide.codingblocks.com/s/305132

#14

no the syntax you used is wrong it will not work. It will not assign inidividual digits as elements.

#15

so how should do it and also pls send the code which is more efficient than this

#16

ill appreciate if you give me reply today

#17

hi @aryaman.harshu sorry for the late reply
you are trying to store the values of a number into an array, so thats what im going to discuss instead of an alternative approach
So a number 1234 should be stored like {1,2,3,4}, right?

int digits = //count no of digits in the numbers and assign it here
int arr[digits];
for (int i = digits-1; i>=0; i--) {
   arr[i] = n%10;
   n = n/10;
}
#18

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