Doubt : List STL Example

#1

Prateek sir here had mentioned that lists cannot be accessed by square brackets but in the List STL example video, “[ ]” has been used. Also explain why we cannot use it

#2

actually we made an array of list when we performed following operation
list<pair<int,int> > *l ;
l=new list<pair<int,int>[n] (here we dynammicaly allocated an array of list)

so when we do l[x] we access xth list in the array of list l

In case of any doubt feel free to ask :slight_smile:
Mark your doubt as resolved if you got your answer

#3

Didn’t get you…are you saying that [ ] can be used for list of array…also isn’t this list of arrays rather than arrays of list?

#4

let me explain you by example :-
when you have
int a[1000];
then a is array of integers

now replace int with list (as list is also a datatype)
we get
list < int> a[1000] ;
now a is array of list

when you do int *l;
l=new int[n] here you dynammically allocate array of int

similarly if you have list *l
l= new list< int >[n] you decide what to call a dynamically allocated array of list or list of array

#5

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