Doubt in the solution

#1

hi, in the ith loop if we traverse from 1 to n-1 it gives the same output and also if I traverse from 0 to less than equal to n i get the same output can you please explain

#2

Hi @mohammednomaan45 pls share ur code

#3

#include
using namespace std;
void bubble_sort(int arr[],int n){

for(int i=0;i<=n;i++){
	for(int j=0;j<=n-i-1;j++){
		if(arr[j]>arr[j+1]){
			swap(arr[j],arr[j+1]);
		}
	}
}

}
int main(){

int n;

cin>>n;
int arr[n];
for(int i=0;i<n;i++){
cin>>arr[i];
}

bubble_sort(arr,n);

for(int i=0;i<n;i++){
cout<<arr[i]<<" ";
}

}

#4

so outer loop should run at max n times. either start from 0 and end at n-1 or start at 1 and end at n… both means the same

#5

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