Doubt in the question

#1

Sir, according to me both the test cases are redundant.

#2

hello @vageesha
no second test case is not.

((a+(b))+(c+d))

we dont have extra () in this case.

this type of brackerting is considered as duplicate ->((something))

#3

Sir, but as per my knowledge redundant brackets are those which when removed do not alter the expression. In this case if we remove the brackets around b, even then the expression remains the same.

#4

for this problem

consdier (b) such case as non redundant.
they have never defined what is b.
it can be (3) or (2+4) or (anything thing).

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#5

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