Doubt in index and pred formula

#1

doubt in index and pred formula

#2

Hey @silpasweta, go through this example and you will understand that,

new_vals = np.unique(vals[:,1],return_counts=True)
The above line will return unique values and their corresponding count,
Suppose now, new_vals = ([1,3,5],[3,1,1]) This means there are 3 points belonging to 1 class, 1 point of 3&5 class each.

index = new_vals[1].argmax()
Now the above line will return index of maximum value second array of new_vals i.e. [3,1,1] so index = 0(since 3 is maximum at 0 idx)

pred = new_vals[0][index]
Now this line will give me the corresponding class having maximum count. so pred = 1.

Hope this resolved your doubt.
Plz mark it as resolved in my doubts section. :blush:

#3

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