Doubt in for loop

#1

why this line is causing error… the expression sqrt(n) will be calculated just once right?
in python (2nd link) it doesn’t raise any error !

#2

hello @prerak_semwal
ss

here u r dividing n by 0 (i=0 in starting) thats why it is giving arithmetic expection error.

#3

@aman212yadav

but why the loop not run for 10 times like in python

#4

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bro why will it excute? it will stop at the first step only becuase u are diving a number by 0. because of which the system will throw exception

in python u are starting from 1 onwards but here it is from 0.

#5

@aman212yadav
I mean if we change i to 1 then it’s not running 10 times …unlike python

#6

use <=
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…
…

#7

@aman212yadav

how would that matter…the loop still doesn’t run for 10 times (in contrast to python)

#8

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use while loop in python if u want similar behaviour.

in python the start and end of iteration get decided at the beginning of first iteration itself after that it does not change(evidentn from the value of i itself).

#9

what do you mean by above ?

So in c++ at every iteration the ending condition is re-computed right? and then the variable i is updated (i++)

#10

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yeah …the condition get reevaluated after every iteration in c++.

i am saying by looking at the value of i , we can say that division of n has no impact on number of iteration