DOUBT IN CODE (Ultra-Fast-Mathematicians Problem)

#1

#include
using namespace std;

int main() {
int n;
cin>>n;

while(n--)
{
	long long int a,b;
	cin>>a>>b;
	cout<<(a^b)<<"\n";
}
return 0;

}

The answer should come as 00111 for the sample test case, but I am getting the answer as only 111. How do I get to print the leading zeroes?

#2

@pratyushnitdgp19_2c287088d77b5893

Instead of taking input as long long int you can take it as a string.
string a, b, ans;
cin>>a>>b;

Implement your logic and print the final ans string. This way you can print leading zeroes.

#3

#include
using namespace std;

int main() {
int n;
cin>>n;
while(n–)
{
string a,b,res;
cin>>a>>b;

	for(int i=0;i<a.size();i++)
	{
		if(a[i]==b[i])
		res[i]=0;
		else
		res[i]=1;
	}

	cout<<res<<"\n";
}

return 0;

}
Sir this code is not printing any output.

#4

@pratyushnitdgp19_2c287088d77b5893

int main() {
int n;
cin>>n;
while(n–)
{
     string a,b,res;
     cin>>a>>b;
     res = a; // assign result to some initial value else it will be an empty string
     for(int i=0;i<a.size();i++){
		if(a[i]==b[i])
		  res[i]='0'; // it should be '0' not 0
		else
		  res[i]='1'; // it should be '1' not 1
     }
     cout<<res<<"\n";
}

return 0;
}
#5

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