Doubt in a Pattern Problem

#1

So here is my code:

Now, I am not understanding the code from line 19 to 27 (i.e. the code inside else block}. I am totally confused in the condition used in while loop( line 22).

#2

Hey @yashsharma4304 in line number 22 what you are doing is you got an even row now let it be 6 , so first you are printing 1 now you have to print 4 zeroes and then again 1 so that total numbers in this line will be 6. That’s the reason we have done col<=row-2 because the two spots are booked for 1 and rest are for zeroes. Hope this would help you :slight_smile:

#3

So, that means there are two 1’s that has already booked first and the last column. Now, does it mean that (the column number 2 is column number 1 for that while loop and column number 5 is column number 4) for that while loop.

#4

Row = 6
Row - 2 = 4
that means Col <= Row - 2
i.e. Col <= 4

and therefore I am asking that the loop will run 4 times. So, actually column 2 is column 1 and column 5 is column 4 for that while loop. Right?

#5

Wait you are getting confused,
Suppose your row is 6 okay,
And in your 6th row you are at column number 1
Here you have to print 1 , now there are 5 more columns left because your row is 6
Now what you have to do is in your 5 more columns you have to add 4 zeroes
Resulting 10000 now you have only one spot left that is your 6th column, here you have to add 1 which gives you a resultant of 1000001 . Hope this would help you in understanding it :slight_smile:

1 Like
#6

Yes, now I understand. Thank you for resolving my doubt. Great Explanation.

#7

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