In modular properties sir told that
(a-b)%m=((a%m)-(b%m)+m)%m
But in this question , sir written
(b-a)%N=0
=> b%N=a%N
Divisible subarray problem
hello @asif_h both the operations evaluate the same result .
if you try to solve this with any example you will also find the satisfactory answer .
first approach that you mentioned is generally implemented when the test cases are larger.
with practice you will learn that there is no major difference between the both .
if you feel that your doubt is cleared please mark this doubt as resolved .
Happy Learning !!
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