Display the number of ASCII- sequence

#1

I am able the display all the ASCII- subsequences, but not able to print the number of ASCII- subsequences. how can I do that?

code-

#include
#include
using namespace std;

//function to print subsequesnces containg ASCII value of the characters
//or the characters of the given string
void findsub(string str, string res, int i){

//base case
if(i == str.length()){

    //if length of the subsequence exceeds 0
    if(res.length() > 0){

        //print the subsequence
        cout << res <<" ";
    }
    
    return;
}


//stores character present at the i-th index of str
char ch = str[i];

//if the i-th character is not included in the subsequence
findsub(str, res, i+1);

//icluding the i-th charachter in the subsequence
findsub(str, res + ch, i+1);

//include the ASCII value of the i-th character in the subsequence
findsub(str, res + to_string(int(ch)), i+1);

}

int main(){

string str;
getline(cin,str);
string res ="";

//stores length of str
int N = str.length();

findsub(str, res, 0);

cout<<endl;



return 0;

}

#2

Hi @tanishqbatra0511,

There is a small mistake in your code, you also need to print a sequence if its length equals 0 means an empty string. So, just change your base condition like this

if(res.length() >= 0)

Now, to count all ASCII sequences just declare a global variable cnt and increment it every time you print a sequence.

int cnt = 0;
void findsub(){
    //base case
    if(i == str.length()){
       if(res.length() >= 0){
            cout << res <<" ";
            cnt++;
       }
        return;
    }
    //do something
}
#3

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#4

yes, got it, thanx for the reply

#5

Hello @tanishqbatra0511,
Welcome :grinning:

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