Did not understand MCQ 1

why the option is C ? please explain

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Q1
What will be the output of the following code? #include<stdio.h>
void main(){
char *p;
char sample_string[]=“codingjunction”;
p=sample_string;
p +=6;
printf("%s",p); }
A) coding
B) codingj
C) junction
D) codingjunction

Answer must be C
p will contain the string “codingjunction”
When you just refer to p…it means it is the base address of the character array
So p+=6…means 6 position ahead of the base address…
So now base address p…is the address where j is there.
printf("%s",p); Now this will print the remaining string from j ie. junction