Dequeue and main function

#1

here in the code after the loop we have used q.dequeue . So how did it skipped the 1 and 7 from the queue . moreover while passing arguments in the main function there is no clarity of the arguments passed, wherein the int argc,char const*argv is not explained throughly

#2

Hey @Agam_virgo
Firstly, in the beginning, we enqueued numbers 1 to 6
Then we performed a dequeue operation, 1 gets dequeued
Then we enqueue 8
so the queue has 2 3 4 5 6 8

#3

argv and argc are how command line arguments are passed to main() in C and C++.

argc will be the number of strings pointed to by argv . This will (in practice) be 1 plus the number of arguments, as virtually all implementations will prepend the name of the program to the array.

The variables are named argc ( argument count ) and argv ( argument vector ) by convention, but they can be given any valid identifier: int main(int num_args, char** arg_strings) is equally valid.

YOU CAN OMIT THEM!! even without using them, your program would work completely fine.

#4

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