what is this out of reach concept that it cannot convert the default integer literal to long type?
Data types practical part 2 and 3
When you type in a number in Java, the compiler automatically reads it as an integer, which is why when you type in (long) 6000000000 (not in integer’s range) it will complain that 6000000000 is not an integer. To correct this, you need to specify 6000000000L.
There are specific suffixes for long (e.g. 39832L), float (e.g. 2.4f) and double (e.g. -7.832d).
If there is no suffix, and it is an integral type (e.g. 5623), it is assumed to be an int. If it is not an integral type (e.g. 3.14159), it is assumed to be a double.
In all other cases (byte, short, char), you need the cast as there is no specific suffix.
The Java spec allows both upper and lower case suffixes, but the upper case version for longs is preferred, as the upper case L is less easy to confuse with a numeral 1 than the lower case l.
By default any integral primitive data type (byte, short, int, long) will be treated as int type by java compiler. For byte and short, as long as value assigned to them is in their range, there is no problem and no suffix required. If value assigned to byte and short exceeds their range, explicit type casting is required.
All this is explained in the videos in course with appropriate examples as well.