CPP Webinar : Pointers [17-Feb-2018]

#1

Why is address of char data not displayed?

#2

This is a special case. When you are taking the address of a char data, you get char * . operator<< interprets that as a C string, and tries to print a character sequence instead of its address.

When you are taking the address of b, you get char * . operator<< interprets that as a C string, and tries to print a character sequence instead of its address.

Try cout << “address of char :” << (void * ) &b << endl instead

#3

why are &character treated as different and what are reason?

#4

I have already mentioned above. Say you store a character in a variable b. Now &b will return a character pointer. So the compiler interprets it as a C string and prints the same character. This is a special case and you can avoid it explicitly by using (void * )