didn’t understand copy constructor logic explained between 5th to 6th minute
Cpp oops - copy constructor
Hello @Divya_321,
Try to relate what sir has explained in the video with the following:
If an object is passed as value to the Copy Constructor then its copy constructor would call itself, to copy the actual parameter to the formal parameter.
Explanation:
When you would write:
Car F = C;
The copy constructor will be invoked/called and C will be passed as the parameter.
When you pass any parameter by value, it’s copy is created and that copy would be excepted by the called function.
But, in this program the parameter passed is an object of the class i.e. C.
So, when the compiler will implicitly create it’s copy, it will call the copy constructor.
Again the entire process will repeat for this call… leading to another.
Hence, an endless chain of call to the copy constructor will be initiated. This process would go on until the system run out of memory.
Hence, in a copy constructor, the parameter should always be passed as reference.
In pass by reference, no copy of parameter is created.
Hope, this would help.
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