Could not understand the equation at the current timestamp. Please help me. https://youtu.be/K_UOxtlAIms?t=346
Could not understand the equation
its fermat little theorm . where are you having the problem?
I am getting problem that how is b = B%(p-1)
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No not at all doubt not cleared
hello @ayusdas2000
we know x^(p-1) mod p => 1 if p is prime number…fermant little theorem
now to calculate (a^b) mod p .
we can write b = (p-1) + (p-1) + (p-1) … + k
where k is remainder we are left with. i.e k=b%(p-1)
substituting value of b
(a^b)mod p = a^(p-1 + p-1 + p-1 + p-1 … + k) mod p
now using property a^(x+y) => a^x * a^y
=> ( a^(p-1) * a^(p-1) * a^(p-1) … a^k )mod p
now we know a^(p-1) mod p =1
=> 1 * 1 * 1 …a^k mod p
=> a^k mod p
substituting value of k
=> a^(b%(p-1) ) mod p