In the above code given by sir while making a copy of the car E as F and then changing the first letter of the name data member (of F), why didn’t the first letter of name E is not changed (because name is a char array which can act as pointer) ?
This doubt is in reference to the shallow and deep copy concept.
@Rooopak_Sharma
The changes would have been reflected if we copied the array pointer value. We copied the data of the name string using strcpy( ) , so only the data gets copied. The pointers of E and F are pointing to two seperate strings which have the same data. Any modification in one of these strings does not reflect in the other one as they are seperate.
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