in the problem discussed around 40 minutes, (keepers-losers one)
if n = 8
then also player 1 can choose 6, so n will become 2 and player 2 will be forced to pick up the 2 coins and so player 1 wins. Then why are only cases with 8k+[1,2,3] considered? 8k + 0 should also be considered right? And if that is the case then how is it any different than the finders-winners situation where we had to reduce it to the closest multiple of a+b, ie 8k in this case
Confusion in keepers-losers problem (q3 of webinar)
We had to tell the n for which it loses, so when a was 3 and b was 5, we lose when it was of the form 8k+1, 8k+2 and 8k+3. It ofcourse wins for 8k.
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