Comparators implementation, function by reference and stl sort function

#1

i have a doubt in this code where the function is passed as reference that will it work if i pass lambda function?? i am really confused with it as in the previous video sort function was taught and sort function can accept a comparator function as well as a lambda function and this video is about explaining the implementation of that sort function i.e. how it works internally.

But if function is passed by reference in this, then i have a doubt that if we pass lambda function it will act as R-value i think and according to move semantics this method of reference is for L-value reference then how sort function works when we even pass lambda function or a comparator function as argument.

please help me by clearing this doubt.

#2

hello @Rajat02

comparator provides logic for comparing two elements.
now it is upto u how u pass it to another function for making comparision, either by making a lambda function or by a general function.

#3

Thank you @aman212yadav for answering,
But can you please tell me are lambda functions passed as R-values??

#4

@Rajat02
what do u mean by L and R value , i dont know these terminologies

#5

@aman212yadav L-values and R-values according to c++ 11 move semantics to give reference to a variable.

#6

@Rajat02
do u have any link or something regarding same

#7

@aman212yadav no that I don’t have it was told by one of my teacher

#8

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