Code failing Test Cases
- If count >= 3 you are just printing first three factors instead of printing,
a = factors[0], b = factors[1], c = n/(a*b)
- If count == 1 and m >= 6,
a = factors[0], b = aa, c = n/(ab)
- if count == 2, and check whether a,b,c are distinct or not
a = factors[0], b = factors[1], c = n/(a*b)
- else no
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sir
- I have corrected point 1 as per your recommendation.
- m >= 6 i guess you meant occur and i have done the changes by removing power function.
- count will only be 2 if there are 2 distinct factor of m and the rest are done .
I need some more of your guidance as solution is still not getting accepted.
Yes, I meant occur.
- If count == 1 and occur >=6, you are distributing like this
a = f, b = f^2, c = f^3 then abc = f^6
So, if n = 2^10, then a = 2, b = 4, c = 8 but then abc = 2^6 != n
So, the correct way is:
a = factors[0], b = aa, c = n/(a b)
- Similarly if count == 2 then your distribution is correct but you are not checking whether a b c are distinct or not.
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Thank you so much sir for guiding me 
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