Chewbacca number

#1

I am failing to add the case when first digit is 9…plz help me

include

using namespace std;

define int long long

int chewbaccanum(int n){
int no = 0,i=1;
while (n!=0)
{
int digit = n%10;
int newdigit = 9 - digit;
if (newdigit<digit)
{
if (0<n<10)
{
if (digit == 9 && newdigit == 0)
{
no += digit*i;
}

       }
       no += newdigit*i;
       
    }
    else
    {
        no += digit*i;
    }
    
   i *= 10;
   n /= 10; 
}
return no;

}

int32_t main(){
int n;
cin>>n;
cout<<chewbaccanum(n);
return 0;
}

#2

kindly share the link of code so that i can modify and run your code

Logic:
if digit is >5 flip that digit otherwise don’t flip
also check some corner cases
a) first digit should not be zero so if first digit is 9 then it should remain unchanged
b) if number is 0 only then output should be 9, not 0.

Reference Code

#3


here is the link to my code…please see it and change the error

#4

code is not saved recheck the link

#5
#6

Modified Code

for input 999
you output 999
but correct output is 900
check the changes in modified code , you have done syntax error at line no 13

#7

so basically it should not be 0<n<10…but why it is it so ???..isn’t both r same??

#8

NO
this is not the correct syntax
correct one is
0<n && n<10

#9

okie…thank you…i get it now

#10

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