Is there any advantage of &ch (character) showing the value instead of address in cout statements? Why does it happen this way?
&ch in cout statement
Hey @diganta_7777
I can’t think of any advantage, I never really came across it after studying it.
The answer to this issue is explained very beautifully in this post.
The brief idea is just that when you do &ch, you get char* data type. So cout interprets char* as a sequence of characters or a string and prints as long as it doesn’t encounter a null in memory.
Got it! Thanks! .
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