Cant solve the problem

#1

Hi im not able to solve the problem im not able to understand how i can know whether its on even place or odd can u help me out?

#2

hi @dharamrajroy_275ef8688612039e
refer this code–>

#include <iostream>
using namespace std;
int main() {
    int n;
    cin>>n;

    int pos = 1;
    int odd_sum = 0;
    int even_sum = 0;

    while(n > 0){
        int x = n%10;
        n = n/10;
        if(pos%2 == 1){
            odd_sum += x;
        }
        else{
            even_sum += x;
        }
        pos++;
    }
    cout<<odd_sum<<endl;
    cout<<even_sum<<endl;
}
#3

hey, if still there is anything do let me know…

#4

no all good thank you for the help

#5

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1 Like
#6

done thanks for help

#7

also i had to ask what does this line do

int x = n%10;
n = n/10;

#8

int x = n%10;
This line extracts the digit.
n = n/10;
This line removes that digit from the number.

#9

what what if the number is of 3 digits

#10

That’s why we have put a while loop so that all digits can be extracted one by one…