Can't able to understand the problem

#1

can’t able to understand the problem

#2

@shubhamkumarsingh,

The logic behind this Problem was pretty simple as we can invert any digit ( 9 - digit) but we need to invert only such digits that will eventually end up giving the smallest number possible.

So, we should invert only digits greater then or equal to 5 as after inverting them, the result gives us smallest number.

For e.g.,

9 - 5 = 4 viz, smaller than the original number that was 5.

9 - 8 = 1 viz, smaller than the original number that was 8.

but 9 - 1 = 8 viz, greater than the original number that was 1.

Important point to consider is, After inverting any digits their should not be trailing zeros that means, if their is 9 at the starting of the number then it must remain the same

Also input can be quite big so use long.

#3

not able to find out why one test case is not passing

#4

@shubhamkumarsingh,
Please share your code: https://ide.codingblocks.com/
select the correct language, copy your code, click on save, share the link

#5

Here is my code

#6

@shubhamkumarsingh,

Can you please share the appropriate code?

#7
#8

@shubhamkumarsingh,
Test case: 999
Your output: 999
Correct output: 900

#9

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