Bitwise operations(((())))))

#1

please explain me how the bool function operated…like i didnt get the turnery operator

#include
using namespace std;

bool isodd(int n)
{
int lsb = (n & 1) == 0 ? 0 : 1; // turnery operator
// lsb == 0 // false
// lsb == 1 // non zero value means true
return lsb;
}

int main()
{
int n;
cin >> n;

if (isodd(n) == true)
{
    cout << n << " is odd" << endl;
}
else
{
    cout << n << " is even" << endl;
}

return 0;

}

#2

@abhinavssr2003_eab0717682969e5c

condition ? expression1 : expression2;

Ternary operator works like, if the condition is true statement 1 is executed else statement 2 is executed. So in the program , lets say the no is even its bitwise and with 1 will always be 0 (as even no end with a zero in binary form) so 0 == 0 ? yes … so will return 0

#3

@abhinavssr2003_eab0717682969e5c,
its function to check odd or even if (n&1) is 0 then its even so its returning 0 else if odd then returning 1

read more here : https://www.geeksforgeeks.org/conditional-or-ternary-operator-in-c-c/

#4

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