Binary number prblm

#1

Given a binary number ,help Von Neuman to find out its decimal representation. For eg 000111 in binary is 7 in decimal. not able to make a approach

#2

Hey @zaid.shamshi4
This is simple binary to decimal conversion what u are not able to understand here.

How to convert binary to decimal

For binary number with n digits:

dn-1 … d3 d2 d1 d0

The decimal number is equal to the sum of binary digits (dn) times their power of 2 (2n):

decimal = d 0×20 + d 1×21 + d 2×22 + …

Example

Find the decimal value of 111001:

binary number: 1 1 1 0 0 1
power of 2: 2^5 2^4 2^3 2^2 2^1 2^0

111001 = 1â‹…2^5+1â‹…2^4+1â‹…2^3+0â‹…2^2+0â‹…2^1+1â‹…2^0 = 57
000111= 0â‹…2^5+0â‹…2^4+0â‹…2^3+1â‹…2^2+1â‹…2^1+1â‹…2^0 = 7

Input binary no as string/char array
and to converte each digit to 0 or 1 use
x-‘0’

For example
string s;
cin>>s;//s is now 000111
 for(int i=s.length()-1;i>=0;i--){//traverse from right to left
      int digit =s[i]-'0';//converte char representation of 0 or 1 to integer digit 0 or 1
}
Why i am getting wrong ans
#3

Refer to this if req

#include <iostream>
using namespace std;
int main() {
    string s;
    cin>>s;
    int value=0;//to store final value
    int pow=1;// for powers of 2
    for(int i=s.length()-1;i>=0;i--){//traverse from right to left
        int digit =s[i]-'0';//converte char representation of 0 or 1 to integer digit 0 or 1
        value += digit*pow; 
        pow=pow*2; 
    }
    cout<<value;

    return 0;
}
#4

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