Basic calculator

#1

#include
using namespace std;
int main(){
char op;
cin>>op;
float num1,num2;
while(op!=‘x’||op!=‘X’){
cin>>num1>>num2;
switch(op){
case ‘+’:
cout << num1+num2;
break;
case ‘-’:
cout << num1-num2;
break;
case '’:
cout << num1num2;
break;
case ‘/’:
if(num2!=0)
cout << num1/num2;
break;
case ‘%’:
if(num2!=0)
cout<<int(num1) % int(num2);
break;
default:
cout <<“Invalid operation. Try again.”;
break;
}} }
I am not able to find error in this code.

#2

You need to use do while loop in this code, and take the input value of character first and check if its ‘x’ or ‘X’ , then simply return 0, or else if its not, then u simply have to take the input values of n1, and n2, and based on the character, you will have the result, This is the basic approach u need to follow up in your code.Basic snippet of code I m sharing here…

do
{
cin>>ch;
if(ch==‘x’ || ch==‘X’ )
{
return 0;
}
else
if(ch==’+’|| ch==’-’ || ch==’/’ || ch==’’ || ch==’%’)
{
cin>>n1>>n2;
}
switch(ch)
{
}
} while(ch!=‘X’|| ch!=‘x’||ch==’+’|| ch==’-’ || ch==’/’ || ch==’’ || ch==’%’ );

#3

#include
using namespace std;
int main(){
char op;
float num1,num2;
do{
cin>>op;
if(op==‘X’||op==‘x’){
return 0;
}
else
if(op==’+’||op==’-’||op==’’||op==’/’||op==’%’){
cin>>num1>>num2;}
switch(op){
case ‘+’:
cout << num1+num2<<endl;
break;
case ‘-’:
cout << num1-num2<<endl;
break;
case '’:
cout << num1num2<<endl;
break;
case ‘/’:
if(num2!=0)
cout << num1/num2<<endl;
break;
case ‘%’:
if(num2!=0)
cout<<int(num1) % int(num2)<<endl;
break;
default:
cout <<“Invalid operation. Try again.”<<endl;
break;
}}while(op!=‘x’||op!=‘X’||op==’+’||op==’-’||op==’/’||op==’’||op==’%’);
}
still not all test cases are passed.why?

#4

I have edited the code… try to submit it now…