Array.count() function

#1

a = “aaaabbcca”
print(a.count(“aaa”)
shouldn’t the output pe 2 because we have two such substrings aaa from start and then aaa from 2nd a
but why it is print 1 as output can u explain

#2

hey @ChiteshBansal ,
its because of the functioning of the count function.
after getting the first occurence it updates the pointer to next index after the substring.
to deal with this you need to work in a bit different way.

#3

Then what is point of this function then

#4

this function basically lacks at the point when the substrings are overlapped with each other.
So , you can use it in the case when this overlapping is not there , and those times it will work fine.

#5

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