Around 30:00 minutes in webinar

#1

why int * or void * is used in cout or in initisation

#2

@tarunluthra solve this doubt

#3

hey @Nikhil-Aggarwal-2320066674901389, due to operator overloading of <<, cout do not print address of char dataype, hence we typecasting the address of char to address of int or void type.