in armstrong axiom,it is given that
X->Y
X->Z
Z->A
gives:X->Y,Z
X->Y,Z,A
X->X
how do we get this solution from the given dependencies?
Armstrong axioms
hello @kani001
are u trying to find closure of X?
if so then
from X we can determine X its obvious
X->X
also from fd X->Y we can determine Y so it should be in closure as well
so
X-> X Y
again from fd X->Z we can determine Z so it should be in closure as well
so
X-> X Y Z
again from fd Z->A we can determine A and becuase Z is in closure of X . A should also be in its closure.
so
X->X Y Z A which is similar to
X->YZA