About the bitmasking process

#1

why to get the MSB of a 32 bit integer do we need to do (number rightshift 31) &1 ?why not 32 in place of 31 while rightshifting?

#2

hello @Senjuti256
positioning is 0 based. 32th bit (from right) is at 31 position .
thats why we do number >> 31 ( to get 32th bit at 1st place).

for example -> 101 (to get 1st bit ) we do 101 >> 0

#3

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#4

@Senjuti256 you have revoked your doubt instead of resolved. If your doubt is still not resolved, you can ask it.

#5

when we do (101 rightshift 0) what does happen actually I mean the number won’t become 010 after the right shift operation thn how can we check whether the 1st bit is set or not?

#6

If you want to check that the ith (x) bit is set or not, then do x&1 . If it gives 1 then it is set , if it’s 0 then it’s not set.

#7

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