About list return behaviour

#1

def extendList(val, list=[]):
list.append(val)
return list

list1 = extendList(10)
list2 = extendList(123,[])
list3 = extendList(‘a’)
print (“list1 = %s” % list1)
print (“list2 = %s” % list2)
print (“list3 = %s” % list3)

#2

Hey @mdiqbal, the ambiguity lies in the lines, list1 = extendList(10) and list3 = extendList(‘a’). Actually when you do not pass the second parameter, than both the statements, receive the same list address, and hence both 10 and ‘a’ are added to same list. You can cross verify this by,

def extendList(val, list=[]):
  list.append(val)
  print(hex(id(list)))  # to print the memory address of list variable
  return list

list1 = extendList(10)
list2 = extendList(123,[])
list3 = extendList("a")
print ("list1 = %s" % list1)
print ("list2 = %s" % list2)
print ("list3 = %s" % list3)

Hope this resolved your doubt.
Plz mark the doubt as resolved in my doubts section. :blush:

1 Like
#3

Resolved and thanks for the solution

#4

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