A better approach to Pattern 19?

#1

Is there a better way we can solve this question , do we have to deal with corner cases explicitly?

#2 
package pattern_practice_questions;

import java.util.Scanner;

public class Pattern19 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int nst = n/2;
        int nsp = 1;
        int rows = 1;
        while (rows <= n) {
            if (rows == 1 || rows == n) {
                for (int cst = 1; cst <= n; cst++) {
                    System.out.print("*");
                }
            } else {
                for (int cst = 1; cst <= nst; cst++) {
                    System.out.print("*");
                }
                for (int csp = 1; csp <= nsp; csp++) {
                    System.out.print(" ");
                }
                for (int cst = 1; cst <= nst; cst++) {
                    System.out.print("*");
                }
                if (rows <= n / 2) {
                    nst -= 1;
                    nsp += 2;
                } else {
                    nst += 1;
                    nsp -= 2;
                }

            }

            System.out.println();

            rows++;

        }
    }
}

This is my code

#3

According to me, for pattern questions, there is just a single approach, mostly, no better alternative.

#4

okay so it’s right if I deal with corner cases using if else?

#5

Yes definitely you can do that

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