char a[] = {‘a’, ‘b’, ‘c’};
string s5(a);
cout << s5;
When i did not put ‘\0’ character at the end of character array ,put a into the string and then printed the string, the output was - abc��a .
What did actually happen which led to the above result?
(if there was not a ‘\0’ then the string should have continued as it does not know the end or if it does then the output should have been - abc)
char a[] = {'a', 'b', 'c'};
string s5(a);
cout << s5;
if u dont put ‘\0’ at the end then it takes garbage value and print result as ‘\0’ is used as a terminator in character array…
char a[] = {'a', 'b', 'c','\0'};
string s5(a);
cout << s5;
if u put ‘\0’ at the end then o/p comes correct ie abc
i hope its clear now??
but if it takes garbage value then how ‘a’ is printed again in abc��a?
^
That’s a random value… run it again and it will give different o/p
yes , i got it 
Thank you so much.
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