Xor profit problem

#1

im using brute force approach but is there any shortcut for this question?

#2

@sktg99 An efficient solution is to consider pattern of binary values from L to R. We can see that first bit from L to R either changes from 0 to 1 or it stays 1 i.e. if we take the XOR of any two numbers for maximum value their first bit will be fixed which will be same as first bit of XOR of L and R itself. After observing the technique to get first bit, we can see that if we XOR L and R, the most significant bit of this XOR will tell us the maximum value we can achieve i.e. let XOR of L and R is 1xxx where x can be 0 or 1 then maximum XOR value we can get is 1111 because from L to R we have all possible combination of xxx and it is always possible to choose these bits in such a way from two numbers such that their XOR becomes all 1.

Hope this helps.

#3

can u explain this by taking an example

#4

Try doing the dry run for 4,5,6,7 on the paper. You will get the funda

#5

i got it thankssssss

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#6

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#7

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