If we n times multiply the matrix M to itself (in other words calculate power(M, n )), then we get the (n+1)th Fibonacci number as the element at row and column (0, 0) in the resultant matrix. Matrix M is?
M = {{1,1}, {0,1}}
M = {{1,1}, {1,0}}
M = {{1,0}, {1,1}}
M = {{0,1}, {1,1}}
isn’t the answer D? It is showing B.Am I wrong?
@abhijeet.srivastava6499
can we have a chat in chat bar??I still have doubts
I mean according to the lecture
transform matrix and F1 vector(for fabinocci [1 1]) if we multiply we get nth term ryt?
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