two testcases are showing the wrong answer . please guide me.
Wrong answer for two test cases
hello @somilgupta4
a) why r u checking for prime. (follow the definition of cb number for checking)
b) consider this number (assuming 1234 is a cb number and 2,3,4 are also cb number)
1234
now what u logic will do . it will first consider (1,then 12 then 123 and then 1234) right?
and because 1234 is cb number and it is valid as well.
u will include it and mark all positions ie position for 1 2 3 and 4 as 1.
and because all ur digit are marked u will not consider any other cb number.
so ur code will print 1.(ie 1234 as only cb number)
but correct answer is 3 i,e (2,3,4)
correct approach->
a) 4 isnt a CB number as divisible by 2 ( correct me if i am wrong ) , but i wld change the condition if u want. ( numbers not divisible by this set are prime only)
b) check the code carefully, if the number has satisfied the condition(of being prime) I increment to the place where j ends.
waiting for reply
i
note -> i m not saying that 4 is cb number. i m telling u to assume that 4 is cb number.
just to explain u why ur code is failing
sir can u please take an example which satisfies the condition ( given for CB number) and rejects my code . i ll understand myself
beacuse it wont consider 1, 12 ,123 ,1234 . since if we get a CB number i increment i to that of j .
yeah right , u will increment to j.
here do a dry run for case. when i=0
and when this is given
lets take 2357( as 2,3,5,7 are CB numbers ) then my code would take 2 as CB number increment the count and pass the index (j) to i
step :-2
i increaments it and now is on first index which is 3 so every individual number would be accessed and count would be incremented.
and i have decleared the string temp outside the j loop so it should refresh the memory everytime i declare it ( according to me )
but if consider 1234, and i=0
then the first cb number u will find is 1234 .
and then u will update ur i with j i,e 3.
which is the last index of the loop . and ur loop will end .
and u will print only 1. (i,e 1234 )
but correct output is 3 ( 2,3,4)
ok sir got it thank you so much sir !
one more doubt sir , my code was compiling successfully up till afternoon now its showing some error .
many of the test cases passed too .
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