Why new length is not updated after inserting a char

#1
#2

Hello @guptanikhil898

When you are executing the following statement:
string s;
You are just creating an object of class string as s.

And initially the size of string is set to 0 as you have not initialized it.
So, the constructor of string class will initialize it with “”.

Now, when you access the index as s[0], you essentially index outside the bounds of the “used” string (i.e. its size).
Thus, while printing s, the compiler will print “” i.e. empty string because assignment s[0]=‘a’ would not update it’s size.

Solution:
s+=‘a’;
or
s=“a”;

Hope, this would help.
Give a like if you are satisfied.

#3

if i want to add one more after ‘a’ then how should i do that

#4

Hey @guptanikhil898,

then use the concatenate operation: s+=‘a’;
as I have done in the code.

#5

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