Here is the code
Why it is going in a infinite loop
Hello @hhiteshbansal_40d12e2460a1738e,
- Instead of comparing their data you should compare pointers,
if(l2==l1)
- each time you iterate over l2 you should make a second pointer pointing to l2
Like this,
while(l1->next!=NULL){
Node* temp = l2;
while(temp>next!=NULL){
if(temp==l1){
return temp;
}
temp = temp->next;
}
l1=l1->next;
}
return NULL;
why are we taking a second pointer temp .
can`t we take l2 instead of temp
also is there is any guarantee that node having same value will have same address in both linklist.
@hhiteshbansal_40d12e2460a1738e,
If two nodes don’t have the same address then our answer could probably be wrong,
for eg-
In this case your answer would be 1 but the correct answer is 3
@hhiteshbansal_40d12e2460a1738e,
If you don’t take temp then while iterating over second while loop, l2 would become null,
and for each node in l1, l2 would be null.
okay got it thanks 
can you tell me my mistake now
@hhiteshbansal_40d12e2460a1738e,
if(temp->next==l1->next){
return temp;
}
Change this,
if(temp==l1){
return temp;
}
now it is showing :-
/bin/run.sh: line 4: 18 Killed ./exe
IT IS STILL GIVING
runguard: warning: timelimit exceeded (wall time): aborting command
runguard: warning: command terminated with signal 15
DURING SUBMITING OF CODE
@hhiteshbansal_40d12e2460a1738e,
There is still one error, instead of writing like this,
while(l1->next!=NULL){
Node*temp=l2;
while(temp->next!=NULL){
It should be,
while(l1!=NULL){
Node*temp=l2;
while(temp!=NULL){
if,
l1 = 1 -> NULL
and l2 = 2 -> 3 -> 1 -> NULL
then o/p would simply be NULL in your case but the correct o/p is 1
Also, you haven’t submitted it even once, please try submitting your solution instead of compiling it.
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