Why is this code not working for this Question?

#1

Why is this code not working for this Question?


#2

hello @cbcao263
remove 2nd if statement of for loop and then try

#3

Sir, I have done this and it was not passing for text case like " ", So I used one more loop for that having in which I calculated Spaces and then used An another condition for(int i=0;i<n;i++)
{
if(s[i]==32)
sp++;
}
if(sp==n)
return 0;

Then It was failing for the condition "a ".

#4

And As You told to remove the second line, What was issue in that Sir?

#5

compiler was treating len++ as an inside statement of if , thats why i said to remove it.

#6

if ur code is still failing then pls share ur updated code with me

#7


This is the code

#8


Even This is not working as I used the {} for the if.

#9 
class Solution {
public:
int lengthOfLastWord(string s) {
    if(s.length()==0)
        return 0;
    int len=0,sp=0;
    int n=s.length();
    int i=n-1;
    // code for skipping all end spaces 
    while(i>=0 && s[i]==' ')
        i--;
    
    
    for(;i>=0;i--)
    {
        if(s[i]==32 and len!=0)
            break;
        
        
        len++;
    }
    return len;
}
};

check now .
basically u need to skip ending spaces and for that i have added while loop.

#10

Accepted Sir,
Basically You have skipped the spaces at last and then you start calculating the word length.
Am I right?

#11

yeah…correct…

#12

Thanks a lot Sir for this Method, found One New Method today :slight_smile:

#13

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