Why is this code(is armstrong number) not giving any output?

#1

#include
#include
using namespace std;
int main() {
int n,count=0;
int sum=0,res,val,dgt,chk;
cin>>n;
val=n;
chk=n;
while(n>0)
{
val=val/10;
count=count+1;
}

while(n>0)
  { 
      dgt=n%10;
      n=n/10;
      res=pow(dgt,count);
      sum=sum+res;

  }
if(sum==chk)
{
    cout<<"true";
}
else
cout<<"false";
return 0;

}

#2

@S19LPDWK0093 Please copy and save the code in coding blocks ide and share its link.

#3
#4

@S19LPDWK0093 You code is not giving any output because it is getting into an infinite loop at line number 10 as n is not being decremented/changed within the loop.Also there is no need for that while loop and count variable as armstrong number is a number whose sum of cube of digits is same as that number.

#5

ok ty replaced val with n and armstrong number is not the number whose sum of cube of digits is same as that number , it depend on how many digits , for 2-digit square, for 3-digit cube

#6

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