Where is my error?

#1

sir, please help me to find out my error --> https://ide.codingblocks.com/s/450035

#2

hello @chandreshmaurya

check now->

#3

sir, if ‘9’ is not at left most. then how will we deal with that ?

#4

. . .
…

when left most is not 9 , then we use the same logic that we are using on other digits.
otherwise if it is 9 then we dont change it

#5

sir, but is there any code to find the " 9 is at left most" ? please mention that .

#6 
		if (r>4 && n!=9) {//added n!=9 ,so that we dont change left most digit if it is 9 
			number+= ((9-r)*l);
		}

that second statement inside the if is for the same purpose.
pls dry run on this case ->
988
for clarity

#7

sir, it’s okay with the dry run. but, i’m not getting code. how do it differentiate between left most 9 and others 9 ?

#8

n will always be greater than 10 . only in last iteration it will be 9 or less than that.

for example->
n=978
in first iteration n=978 , r=8 , in the end we divide n by 10 so now n will be 97
in second itertion n=97, r=7, in the end we divide n by 10 so now n will be 9
in third itertion(last iteration becuase we have only 3 digit no , it means we are modifying left most digit) n=9, r=9, in the end we divide n by 10 so now n will be 0.
note how n changes , it was less than 10 only in last iteration

#9

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