When condition get true means we find the sum equal to target

#1

even after finding the sum equals to target i am not increasing the i value and not decreasing the j value by 1
still i am getting the right answer and passsed all test cases
but as u taught us that u have to increase and decrease the value of i and j by 1;

code:

using namespace std;
#include
#include
int main()
{
int n,target;
cin>>n;
int a[n];

for(int i=0;i<n;i++)
cin>>a[i];
cin>>target;
sort(a,a+n);

int i=0,j=n-1;
while(i<j)
{
	if((a[i]+a[j])==target)
	{
		cout<<a[i]<<" and "<<a[j]<<endl;
		//i++;
		//j--;						//doubt ??
	}
	if((a[i]+a[j])<target)
	i++;
	else
	j--;
}

}

#2

@n.nishchaya2000
Because of the if else statements.
if((a[i]+a[j])<target)
i++;
else
j–;
this if else automatically decreases the value of j.

#3

so even if first condition get true it will check rest of two also if and else as well means

#4

you have 1 if condition and 1 if else condition if(a[i] + a[j] == target) the else of second statement would work.

#5

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