Whats is the problem?

#1

Head function gets altered even though i am passing it to rev function by value and not by reference

#2

bro!
even thought u dont not pass head as reference but u are updating the links in the reverse function so the head is being updated.

due to link updationg the head is linked list is getting updated

#3

then what is the difference between passiing it by reference or value?

#4

passing it by reference means that u are updating the value at the address
by value means that temporary updated are made in the function call

#5

I mean what difference does it make in this case

#6

bro there will be no difference
since u are updating the links pass it by value or by reference your head is getting updated

#7

How can that be. Why would i pass it by reference if it gets updated otherwise also?

#8

and if it did, then wouldnt the print function in my code alter head node?

#9

void reverse(node* head)
{
Node* current = head;
Node *prev = NULL, *next = NULL;

    while (current != NULL) { 
        next = current->next; 
        current->next = prev; 
        prev = current; 
        current = next; 
    } 
    head = prev; 
}

tell me one thing this is a code of reversing the linked list
i am passing head as value and not as refernce in function paramter
if in the int main() function u try printing the linked list wont the reverse be printed

like when the links are being updated how do u expect the head not getting changed

print function is just traversing the LL using the head node

#10

but in the print function also head is updated to head->next at each step

#11

brrrooooo
u are changing the link

u are updating the internal linked the linked are reverseddd…
please try the reverse function on pen paper u update the links
in the print u just vo ahead, u aint reversing any link

#12

okay i got it.
Thanks

#13

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