What is the use of the following statement in the solution?

#1

(s[j] - ‘0’) this part in stoint

#2

hello @vipulch

it convert integer character to number .
i.e it converts charcter like ‘8’ to 8.

note ‘8’ is charcter , 8 is integr.

so if u subtract ‘0’ from any such numeric charcter then u will get number.

in the video we doing the same thing

#3

that means char-char gives integer?

#4

or is it because we are putting the value in an integer?

#5

char is nothing but number only , compiler use characters ascii values for any arithmetic operation.

for example if u write ‘8’ then compiler use its ascii number which is 56.
similarly ‘0’ is equivalent to number 48.

so when u subtract ‘8’-‘0’ then its ascii value is used .
i.e ‘8’-‘0’ is 56-48 which is 8

1 Like
#6

now i got it, thanks!

#7

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