What is the error?

#1

void display(node* root)
{
if(root==NULL)
{
cout<<“END”;
return;
}
cout<<(root->left)->data<<" => “<data<<” <== "<<(root->right)->data;
display(root->left);
display(root->right);
}
Can u please tell what’s wrong with this code?

#2

Hello @Hk199977,

The following statement will produce a run-time error for the nodes with either 1 child or no child:
cout<<(root->left)->data<<" => “<data<<” <== "<<(root->right)->data;

Solution:
First, check if it’s left and right child exists or not.
If it does,
then print it.

Following is the correct implementation of the display function:

Hope, this would help.
Give a like if you are satisfied.

#3

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